-27u^2=-39

Solution for -27u^2=-39 equation:

-27u^2=-39

We move all terms to the left:

-27u^2-(-39)=0

We add all the numbers together, and all the variables

-27u^2+39=0

a = -27; b = 0; c = +39;
Δ = b2-4ac
Δ = 02-4·(-27)·39
Δ = 4212
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{4212}=\sqrt{324*13}=\sqrt{324}*\sqrt{13}=18\sqrt{13}$
$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-18\sqrt{13}}{2*-27}=\frac{0-18\sqrt{13}}{-54}
=-\frac{18\sqrt{13}}{-54}
=-\frac{\sqrt{13}}{-3}
$
$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+18\sqrt{13}}{2*-27}=\frac{0+18\sqrt{13}}{-54}
=\frac{18\sqrt{13}}{-54}
=\frac{\sqrt{13}}{-3}
$